The role of the direction in tissue P systems with cell separation

Tissue P systems with cell separation where the communication among cells is performed by means of symport and antiport rules are able to efficiently solve computationally hard problems in a feasible time by a space-time trade off. Symport and antiport rules formally capture the cases where a number...

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Detalles Bibliográficos
Autores: Macías Ramos, Luis Felipe, Martínez del Amor, Miguel Ángel, Pérez Jiménez, Mario de Jesús, Riscos Núñez, Agustín, Valencia Cabrera, Luis
Tipo de recurso: artículo
Estado:Versión publicada
Fecha de publicación:2014
País:España
Institución:Universidad de Sevilla (US)
Repositorio:idUS. Depósito de Investigación de la Universidad de Sevilla
OAI Identifier:oai:idus.us.es:11441/142813
Acceso en línea:https://hdl.handle.net/11441/142813
https://doi.org/10.25596/jalc-2014-185
Access Level:acceso abierto
Palabra clave:Membrane Computing
Tissue P Systems
Cell Separation
Symport/ antiport rules
Computational complexity
Descripción
Sumario:Tissue P systems with cell separation where the communication among cells is performed by means of symport and antiport rules are able to efficiently solve computationally hard problems in a feasible time by a space-time trade off. Symport and antiport rules formally capture the cases where a number of chemical substances pass through a membrane at the same time, with the help of each other, either in the same direction (symport) or in opposite directions (antiport). The present paper investigates the role of the direction in communication rules from a computational complexity point of view. More precisely, the efficiency of tissue P systems with cell separation is analyzed in the case when their communication rules are all of the same type: either symport rules or antiport rules. The main result is that in the framework of tissue P systems with cell separation, passing from using only symport rules to using only antiport rules amounts to passing from non-efficiency to efficiency, assuming that P ≠ NP.